(5x^2-2=2x-11)-(3x^2+8x-7)

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Solution for (5x^2-2=2x-11)-(3x^2+8x-7) equation: 



(5x^2-2=2x-11)-(3x^2+8x-7)

We move all terms to the left:

(5x^2-2-(2x-11)-(3x^2+8x-7))=0



We calculate terms in parentheses: +(5x^2-2-(2x-11)-(3x^2+8x-7)), so:

5x^2-2-(2x-11)-(3x^2+8x-7)

determiningTheFunctionDomain
5x^2-(2x-11)-(3x^2+8x-7)-2

We get rid of parentheses

5x^2-3x^2-2x-8x+11+7-2

We add all the numbers together, and all the variables

2x^2-10x+16

Back to the equation:

+(2x^2-10x+16)



We get rid of parentheses

2x^2-10x+16=0

a = 2; b = -10; c = +16;
Δ = b2-4ac
Δ = -102-4·2·16
Δ = -28
Delta is less than zero, so there is no solution for the equation

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